→
a
∘
(
→
b
+
→
c
)
=
a
1
∘
(
b
1
+
c
1
)
+
a
2
∘
(
b
2
+
c
2
)
=
(
a
1
⋅
b
1
+
a
1
⋅
c
1
)
+
(
a
2
⋅
b
2
+
a
2
⋅
c
2
)
=
→
a
∘
→
b
+
→
a
∘
→
c
→
a
∘
(
→
b
+
→
c
)
=
a
1
∘
(
b
1
+
c
1
)
+
a
2
∘
(
b
2
+
c
2
)
=
(
a
1
⋅
b
1
+
a
1
⋅
c
1
)
+
(
a
2
⋅
b
2
+
a
2
⋅
c
2
)
=
→
a
∘
→
b
+
→
a
∘
→
c
\begin {array} {l} \vec a \circ {\vec b + \vec c}
Created with Highstock 2.0.4
0
1
2
3
4
5
6
7
8
9
10
0
a
a
1
∘
1
b
1
\end
1
r
1
y
1
Lisa
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