v 5.3
E
1
=
E
10
exp
[
i
(
ω
t
−
k
1
r
+
δ
1
)
]
=
E
10
exp
(
i
φ
1
)
exp
(
i
ω
t
)
E
2
=
E
20
exp
[
i
(
ω
t
−
k
2
r
+
δ
2
)
]
=
E
20
exp
(
i
φ
2
)
exp
(
i
ω
t
)