v 2.15
E
0
Σ
=
(
E
01
+
E
02
cos
δ
)
2
+
(
E
02
sin
δ
)
2
=
E
2
01
+
E
2
02
+
2
E
01
E
02
cos
δ
E
0
Σ
=
(
E
01
+
E
02
cos
δ
)
2
+
(
E
02
sin
δ
)
2
=
E
01
2
+
E
02
2
+
2
E
01
E
02
cos
δ
Close
Log in
Books
Repository
eAnswer
ePortfolio
Close
Log in
Books
Repository
eAnswer
ePortfolio
Log in
New user
OK
Error
Forgot?
Log in
Register
Recover
OK
Error
Change