v 4.17

\frac{E_{r 0}^{⊥}}{E_{i 0}^{⊥}} = - \frac{\sin (α - γ)}{\sin (α + γ)}

${\frac{E_{r0}^\perp}{E_{i0}^\perp} = -\frac{\sin ( \alpha - \gamma)}{\sin(\alpha + \gamma)}}$

Error