\frac{n_{2}}{n_{1}} = N_{21} = \frac{\sin α}{\sin γ}

${\frac{n_2}{n_1} = N_{21} = \frac{\sin \alpha}{\sin \gamma}}$

Close
Log in
Books
Repository
eAnswer
ePortfolio

Close
Log in
Books
Repository
eAnswer
ePortfolio

Log in
New user

OK

Error

Forgot?

Sign in with GoogleSign in with Google

OK

Error