d
E
φ
=
E
0
b
d
x
exp
[
i
(
ω
t
−
k
Δ
)
]
=
E
0
b
d
x
exp
(
i
ω
t
)
exp
[
−
i
k
[
(
n
−
1
)
d
+
x
]
sin
φ
]
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