$${\frac{V_1}{V_2} = \frac{\rho_{Cu}}{\rho_{H_2O}} = \frac{{8,92}\,\mathrm{g/cm^3}}{{1,00}\,\mathrm{g/cm^3}} = {8,92}{}\quad\Rightarrow\quad V_1 = {8,92}{}V_2}$$