l_{C} = \frac{3 ρ_{1} + ρ_{2}}{ρ_{1} + ρ_{2}} \frac{l}{4} ⟹ \frac{l_{C}}{l_{A}} = \frac{3 ρ_{1} + ρ_{2}}{ρ_{1} + 3 ρ_{2}}

${l_C = \frac{3\rho_1 + \rho_2}{\rho_1+\rho_2}\frac{l}{4} \implies \frac{l_C}{l_A} =\frac{3\rho_1 + \rho_2}{\rho_1+3\rho_2}}$

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