ρ_{v} = \frac{2 ρ p_{m}}{3 p_{m} - 2 p} = \frac{2 \cdot 1 \cdot 100}{3 \cdot 100 - 2 \cdot 110} = \frac{200}{80} = 2, 5 g / c m^{3}

${\rho_v = \frac{2\rho p_m}{3p_m-2p} = \frac{2\cdot 1\cdot 100}{3\cdot 100-2\cdot 110} = \frac{200}{80} = {2,5}\,\mathrm{g/cm^3}\quad}$

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