V = \frac{P s}{v ρ} = \frac{58 k W \cdot 100 k m}{90 k m / h \cdot 35 M J / l} \approx 6, 6 l

${V = \frac{Ps}{v\rho} = \frac{{58}\,\mathrm{kW}\cdot {100}\,\mathrm{km}}{{90}\,\mathrm{km/h}\cdot {35}\,\mathrm{MJ/l}} \approx {6,6}\,\mathrm{l}}$