Δ λ < \frac{λ^{2}}{2 h} = \frac{(6, 56 \cdot 10^{- 7})^{2}}{2 \times 10^{- 2}} = 1, 6 \cdot 10^{- 11} m = 0, 016 n m

${\Delta \lambda < \frac{\lambda^2}{2h}=\frac{(6,56 \cdot 10^{-7})^2}{2 \times 10^{-2}}=1,6 \cdot 10^{-11} \, \mathrm{m}=0,016\, \mathrm{nm}}$

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