\sin φ_{2} - \sin φ_{1} = 2 \cos \frac{φ_{2} + φ_{1}}{2} \sin \frac{φ_{2} - φ_{1}}{2} = \cos φ Δ φ = \frac{λ_{2} - λ_{1}}{d}

${\sin \varphi_2 - \sin \varphi_1 = 2 \cos \frac{\varphi_2 + \varphi_1}{2} \sin \frac{\varphi_2 - \varphi_1}{2} = \cos \varphi \Delta \varphi = \frac{\lambda_2 - \lambda_1}{d}}$

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