$${\lambda_{min} = \frac{hc}{K_0} = \frac{(4,14 \times 10^{-15}\, \mathrm{eV \cdot s})(3,00 \times 10^8\, \mathrm{m/s})}{35,0 \times 10^3\, \mathrm{eV}} \\ 3,55 \times 10^{-11}\, \mathrm{m} = \underline{\underline{35,5\, \mathrm{pm}}}}$$