How much heat did the water gain?

Use a calculator and calculate how much heat the water in the calorimeter gained when the hot test object cooled.

What we are calculating here

In the experiment, we placed the test object that was in hot water into cold water. In the heat exchange, the temperatures of the test object and the cold water equalized, i.e. the hot test object cooled down and the temperature of the cold water rose. We calculate how much energy reached the water from the test object in the heat exchange.

In the experiment of the previous worksheet, such test data were obtained

Test object mass $m_{k}$ ( $k g$ )
Mass of cold water $m_{v}$ ( $k g$ )
Cold water initial temp $t_{v 1}^{\circ}$ ( $^{\circ} C$ )
Initial temperature of the test object (hot water temperature) $t_{k 1}$ ( $^{\circ} C$ )
The final temperature of the cold water and the test object $t^{\circ}$ ( $^{\circ} C$ )

Calculator: amount of heat during heating and cooling of bodies

The calculator calculates the amount of heat required to heat bodies from a substance or the amount of heat released when they cool down, using the formula $Q = c m Δ t$ . When using the calculator, enter the data in the table. The answer appears in the last row of the table.

Specific heat $c$ of matter	$\frac{J}{^{\circ} C \cdot k g}$
Mass $m$	$k g$
Initial temperature $t_{1}^{\circ}$	$^{\circ} C$
Final temperature $t_{2}^{\circ}$	$^{\circ} C$
Temperature change $Δ t$	$^{\circ} C$
Internal energy change $Q = c m Δ t$	$J$ *

* A negative result indicates that the internal energy of the body decreased. A positive result indicates that the internal energy of the body increased.

The table shows the specific heats of several well-known substances.

Answer

The cold water in the calorimeter gained (

J

)