$${B= \frac{(4\pi \times 10^{-7} \text T \cdot \text m/\text A)}{4\pi} \frac{(10 \times 10^{-6} \text A)(1\times 10^{-3}\text m)}{(2 \times 10^{-2} \text m)^{2}}\sin90^{\circ}}$$